Saturday 28 July 2018

Math : Word Problem

Two tankers contain 680 liters and 850 liters of diesel respectively. Find the maximum capacity of a container which can measure the diesel of both tankers in exact number of times.

Given,
Total number of tankers = 2
first tanker contains 680 liters
second tanker contains 850 liters
we have to find,
the maximum capacity of a container which can measure the diesel of both tankers
which means we have to find the HCF (Highest common factor)
lets find the factors for 680 and 850
680 =  2*2*2*5*17
850 = 2*5*5*17
HCF = 2*5*17 = 170
So, 170liters container is common for 680liters tanker and 850 liters tanker to fill the tankers in exact number of times
170 *4 = 680
hence to fill 680 liters tankers, 4 times of 170liters container be used
170 * 5 = 850
hence to fill 850 liters tankers, 5 times of 170 liters container be used.

Friday 6 July 2018

Grade 6 : Math : Exercise 1.2

1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days?

Given,
Exhibition was held for four days
Number of tickets sold on first day = 1094
Number of tickets sold on second day = 1812
Number of tickets sold on Third day = 2050
Number of tickets sold on fourth day = 2751
now, we have to find the total number of tickets sold on all four days
which implies
we have to add all the four days tickets 
that is,
= 1094 + 1812 + 2050 + 2751
= 7,707 tickets

2. Shekar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

Given,
Total number of scores Shekar scored = 6980 runs
Number of scores he wants to complete = 10,000 runs
we have to find how many more runs he need
that is, he wants to reach 10,000 runs from 6,980 runs
which implies we have to subtract
= 10,000 - 6,980
=3,020 runs

3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?

Given,
Number of votes successful candidate has secured = 5,77,500 votes
Rival has secured = 3,48,700 votes
we have to find at what margin did the successful candidate win the election
which means in what difference did the successful canditate win
that is, = 5,77,500 - 3,48,700
            = 2,28,800 votes

4. Kirti bookstore solds books worth Rs 2,85,891 in the first week of June and books worth Rs 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

Given,
First week, bookstore solds books worth = Rs 2,85,891
Second week, bookstore solds books worth = Rs 4,00,768
The sale for the two weeks together (means add two weeks worth ) 
                                                              = 2,85,891 + 4,00,768
                                                              = Rs 6,86,659
Also we have to find in which week the sale greater
4,00,768 > 2,85,891
so, second week sale is greater
if we find their difference = 4,00,768 - 2,85,891
                                           = Rs 1,14,877 worth greater than first week sale

5. Find the difference between the greatest and the least number that can be written using the digits 6,2,7,4,3 each only once.

Given,
digits given = 6,2,7,4,3
Greatest number using the given digits only once = 76432 (go from highest to lowest)
Least number using the given digits only once = 23467 (from lowest to greatest)
Their difference = 76432 - 23467
                           = 52,965

6. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?

Given,
A machine manufactures 2,825 screws per day
we have to find how many it produce in the month of january
there are 31 days in January
so, total number of screws it produced in january = 31*2,825
                                                                                = 87,575 Screws

7. A merchant had Rs 78,592 with her. Sha placed an order for purchasing 40 radio sets at Rs 1200 each. How much money will remain with her after purchase?

Given,
Amount merchant had = Rs 78,592
She wanted to purchase 40 radio sets
The cost of one radio set = Rs 1200
so, the cost of 40 radio sets = 40 * 1200
                                           = Rs 48,000
the remaining amount she had after purchasing = 78,592 - 48,000
                                                                            = Rs 30,592