Sunday, 15 April 2018

Grade 5 : Math : Exercise 1B

1. How many ones, tens, hundreds, thousands, ten thousands and lakhs are there in the number 8,00,000?

We read the number 8,00,000 as Eight lakhs which means

there are 8,00,000 ones in the number.
to find how many tens in the number, we have to divide the number by 10

that is,
8,00,000/10 = 80,000
hence there are 80,000 tens in the number 8,00,000
 

similarly to find how many hundreds in the number, we have to divide the number by 100
that is,
8,00,000/100 =8,000
hence there are 8,000 hundreds in the number 8,00,000

similarly to find how many thousands in the number, we have to divide the number by 1000
that is,
8,00,000/1000 =800
hence there are 800 thousands in the number 8,00,000

similarly to find how many ten thousands in the number, we have to divide the number by 10,000
that is,
8,00,000/10,000 =80
hence there are 80 ten thousands in the number 8,00,000

similarly to find how many lakhs in the number, we have to divide the number by 1,00,000
that is,
8,00,000/1,00,000 =8
hence there are 8 lakhs in the number 8,00,000


2. Write in figures (with commas)
a. Eight lakh thirty nine thousand twenty three
first let we write its place like,
L TTh Th H T O   (from right to left, we can stop till lakhs since the highest place is lakhs in the given figure)
eight lakhs, twenty nine thousand, twenty three
8,29,023 (no hundreds so hundreds place takes the value 0)

b. Twenty lakh nine hundred five

TL L TTh Th H T O
20,00,905

c. Thirty five thousand eight hundred fifty seven
 

TTh Th H T O
35,857

d. Four crore thirty seven lakh nineteen thousand
C TL L TTh Th H T O
4,37,19,000

3. Compare using < or > or =.

a. 5,87,90,456 _______ 5,78,23,567

Step 1:

First we have to check the number of digits on both side
which side has higher number of digits that number is greater '>'
Left side = 8digits
Right side = 8digits
both the sides have same number of digits
so lets move on to step 2

Step 2:

Compare each number from left to right
left side =5
right side =5
both are same,now lets move to the next number
left side = 8
right side = 7
8 is greater than 7
hence left side number > right side number
that is,
 5,87,90,456  >  5,78,23,567

b. 90,40,908________9,04,908 

here, left side number has higher number of digits
hence

90,40,908 > 9,04,908

c. 8,20,45,899 _______ 8,20,54,899

here, both are having same number of digits
as per step2, left side number is lesser than right side number
that is,
8,20,45,899 < 8,20,54,899

d. 1,40,10,178 ______ 1,40,10,720

here, both are having same number of digits
as per step2, left side number is lesser than right side number
that is,
 1,40,10,178 < 1,40,10,720

4. Make the smallest and greatest 7 digit numbers.

a. 5 , 8 , 2 , 9 , 1 , 1 , 8

To form the smallest number, arrange the given numbers in ascending form (smallest to greatest)
here,
11,25,889
To form the greatest number, arrange the given numbers in decending form (greatest to smallest)
that is,
98,85,211

b. 4 , 7, 1 , 9 , 0 , 6 , 7

To form the smallest number, arrange the given numbers in ascending form (smallest to greatest)
here, 0 is the smallest number but if we use 0 in 1st place then the number would be,
014677 = 14677 (which is not a 7 digit number,it became 6 digit number)
so we have to place 0 in 2nd place that is,
10,46,779
To form the greatest number, arrange the given numbers in decending form (greatest to smallest)
that is,
97,76,410

5. Make the smallest and greatest possible 8digit numbers by repeating the digits.

a. 3 , 6 , 1 , 7 , 8 , 9 , 2

 Given that we can repeat the digits.
there are only 7 digits which means we can repeat any one digit
To make the smallest possible 8 digit, we can repeat smallest digit twice
here, the smallest digit is 1 so,
1,12,36,789
To make the greatest possible 8 digit, we can repeat greatest digit twice
here, the greatest digit is 9 so,
9,98,76,321

b. 4 , 7 , 1, 0 , 3 , 5

given, there are 6 digits, but we have to frame 8digit numbers
so
To make the smallest possible 8 digit, we can repeat smallest digit thrice
here, the smallest digit is 0
since smallest digit is 0, it shouldnt be in 1st position
hence, 1,00,03,457

To make the greatest possible 8 digit, we can repeat greatest digit thrice
here, the greatest digit is 7 so,
7,77,54,310

6. Give the number before

a. 45,69,500

To find the previous number just subtract 1 from the number
so,  45,69,500 - 1 = 45,69,499

b. 87,16,000

87,16,000 - 1 = 87,15,999

c. 5,10,000
5,10,000 - 1 = 5,09,999

d. 20,00,000

20,00,000 - 1 = 19,99,999

7. Give the number after.

a. 9,26,499

To find the next number just add 1 to the number
so, 9,26,499 + 1 = 9,26,500

b. 79,98,999

79,98,999 + 1 = 79,99,000

c. 99,99,999

99,99,999 + 1 =1,00,00,000

d. 1,98,97,950

1,98,97,950 + 1 = 1,98,97,951

8. If you are 10years old, you would have lived 52,56,000 minutes. Compare the numbers given below and match the age to the minutes lived. Do not calculate. Match by putting the numbers in ascending order. One has done for you.
Age 11 - 57,81,600 (given), age12, age13, age14, age15 and minutes 68,32,800 - 63,07,200 - 73,58,400 - 78,84,000

Lets arrange in ascending (smallest to greatest) of both age and minutes correspondingly,

Age 11 - 57,81,600

Age 12 - 63,07,200

Age 13 - 68,32,800

Age 14 - 73,58,400

Age 15 - 78,84,000





Wednesday, 11 April 2018

Grade 5 : Math : Exercise 1A

1. Give the place value of the black digit.

a) 89,00,345

9 is in lakhs position.
hence the place value is 9*1,00,000 = 9,00,000.

b) 30,34,112

3 is in ten lakhs position.
hence the place value of 3 is 3*10,00,000 = 30,00,000.

c) 87,93,389

3 is in thousands position
hence the place value of 3 is 3*1000 =3000

d) 2,67,23,592

2 is in crores position
hence the place value of 2 is 2*1,00,00,000 =2,00,00,000

e) 7,08,19,004

1 is in ten thousands position
hence the place value of 1 is 1*10,000 = 10,000.
2. Give the word form and the expanded notation for these numbers.

 a) 67,09,654

60,00,000 + 7,00,000 + 0 + 9,000 + 600 + 50 + 4

b) 9,83,10,809

9,00,00,000 + 80,00,000 + 3,00,000 + 10,000 + 0 + 800 + 0 + 9

c) 2,10,23,008

2,00,00,000 + 10,00,000 + 0 + 20,000 + 3,000 + 0 + 0 + 8

d) 45,00,091

40,00,000 + 5,00,000 + 0 + 0 + 0 + 90 + 1

3. Give the standard numeral for :

a) 4,00,00,000 + 60,00,000 + 5,00,000 + 40,000 + 200

4,65,40,200

b) 90,00,000 + 60,00,000 + 3,000 + 6

9,60,03,006

c) 6,00,00,000 + 5,00,000 + 20

6,05,00,020

d) 30,00,000 + 9,00,000 + 7,000 + 80

39,07,080



Monday, 17 July 2017

Math KG : Worksheet 5 : Subtracting numbers by counting back

1 Fill in the blanks 

a) 6 - 1 = _________

Step 1

Check whether its + or -

here its -

Step 2 

find the smallest number

here the smallest is 1

leave one finger

Step 3 

now lets look for the another number which is 6 here

since its - we have to count back

we left one finger : already we are having 6 - count backwards which is 5

hence  6 - 1 = 5

b) 5 - 4 = ________

Step 1

Check whether its + or -

here its -

Step 2 

find the smallest number

here the smallest is 4

lets leave four fingers

Step 3 

now lets look for the another number which is 5 here

since its - we have to count back

we left four fingers : already we are having 5 - count backwards

first finger goes with 4
second finger goes with 3
third finger goes with 2
fourth finger goes with 1

hence  5 - 4 = 1

2 Write the subtraction sentences in the boxes provided. Then fill in the blanks.

a) what is the differences between 10 and 6?

Differences which means we have to do subtraction

so  the subtraction sentence is 10 - 6 = ____

now lets find 10-6 = ?

Method 1

we can use number tracks to find the differences

first in the number track, mark 10 and 6

now lets check to reach 6 from 10 how many steps we have to move





hence 10 - 6 = 4

Method 2

Step 1

Check whether its + or -

here its -

Step 2 

find the smallest number

here the smallest is 6

lets leave six fingers

Step 3 

now lets look for the another number which is 10 here

since its - we have to count back

we left four fingers : already we are having 10 - count backwards 

first finger goes with 9
second finger goes with 8
third finger goes with 7
fourth finger goes with 6
fifth finger goes with 5
sixth finger goes with 4

hence  10-6 = 4




Tuesday, 11 July 2017

Math KG : Addition and subtraction : Worksheet 3

5. Fill in the missing numbers


a)











Step 1

we have to make the numbers inside the dotted box to be 10

so,











Step 2

Inside the dotted box, we have 7 and we need to find another number
Both together should make 10

to reach 10 from 7 lets see how many steps we have to move forward






so 7 + 3 = 10











Step 3

now we should check what number if we add with 3 will get 9
that is, to reach 9 from 3 lets see how many steps we have to move forward






so 3 + 6 = 9
hence 











9 + 7 = 16
6 + 10 = 16

d)











Step 1


we have to make the numbers inside one of the dotted box to be 10










Step 2

Inside the dotted box, we have 2 and we need to find another number
Both together should make 10


to reach 10 from 2 lets see how many steps we have to move forward







so 2 + 8 = 10











Step 3

now we should check what number if we add with 8 will get 9

that is, to reach 9 from 8 lets see how many steps we have to move forward






8 + 1 = 9











Step 4

now, 4 and 1 together make 5 that is 4 +1=5










hence 2 + 9 + 4 = 15
also 10 + 5 = 15


Sunday, 9 July 2017

Math KG : Adding numbers by using number pairs

Addition

Addition is bringing two or more numbers(or objects) together to make a new total

Example

Jim has 2 candies and Tim has 5 candies

both together has 2 + 5 which is 7 candies in total

we are having many methods to teach addition to the kids

Method 1 ( Using fingers )

Number of candies Jim has = 2
Number of candies Tim has = 5

2 is the smallest number , so leave two fingers

one finger goes with 6 and second finger goes with 7 ( since we are adding we have to move forward from 5)

hence total candies = 7

Method 2 (Using Number tracks)

Number of candies Jim has = 2
Number of candies Tim has = 5

here the number track

1 2 3 4 5 6 7 8 9 10 11

lets start with Jim who has 2 candies, so lets mark on 2

1 2 3 4 5 6 7 8 9 10 11

now lets go to Tim who has 5 candies, so lets move 5 steps forward

1 2 3 4 5 6 7 8 9 10 11

we reached on 7.

Hence total candies = 7

Making 10

Example : 7 + 6

lets consider, we have 7 RED candies and 6 GREEN candies

0 0 0 0 0 0 0 0 0 0 0 0 0

now lets place 10 black candies below this

0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0

to match this black candies with the above row, 

0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0

so we can write this 7 + 6 = 7 + 3 + 3 = 10 + 3

Question 1


here we go,

first we make the dotted box into 10, that is











now we have to reach 10 from 5









so to reach 10 from 5 we need 5 more steps ahead










now lets fill the last circle. here we have to reach 11 from 5







so to reach 11 from 5 we need 6 more steps ahead











11 + 5 = 16
6 + 10 =16



Monday, 3 July 2017

Math KG : Symmetry

Symmetry

Symmetry is when one shape becomes exactly like another if you flip , slide or turn it. That is symmetry is Reflection or a mirror image.

Line of Symmetry


Line of Symmetry is the imaginary line where we could fold the image and have both halves match exactly. 




Those are some examples of Symmetry and those lines are line of symmetry.










Non Symmetry




 Those are some Non Symmetrical shapes